Question

c^2=8c

Answer 1

no that isn't the original problem... the original problem is c^2=8c how do you get from that to c^2-8c=0

Answer 2

ok...

Answer 3

that doesnt help though

Answer 4

There is an old saying, "What one does to one side of the equation, he must do unto the other.
c^2=8c
Now subtract 8c from both sides.
Now you have:
c^2-8c=8c-8c
c^2=0

Answer 5

thank you

Answer 6

OOOPs, typo alert that last line should be c^2-8c=0

Answer 7

I think you get the general idea.

Answer 8

no now i am completely confused again....

Answer 9

I subtracted 8c from both sides getting:
c^2-8c=8c-8c but we know 8c-8c=0 so we have
c^2-8c=0

Answer 10

so then what do you do?

Answer 11

Then you do what Luis Rivera did.
First he factored the left hand side getting
c(c-8)=0 Do you see how that is the factored (c^2-8c)?

Answer 12

yes

Answer 13

then what?

Answer 14

Now here is an important tip. When you have a product of factors equal to 0, then at least one of the factors has to be zero, or maybe all of them will be zero.

Answer 15

ok thanks for the tip. can you explain the rest of the problem please?

Answer 16

how do you go from c(c-8)=0 to c=8?

Answer 17

So with that tip in mind and "c(c-8)=0"
then c=0 or c-8=0
if c-8=0, then c=8 you test them to verify

Answer 18

If c-8=0 you solve by adding 8 to both sides
c-8+8=0+8
c=8

Answer 19

there has to be an easier way to do this this makes no sense

Answer 20

Now for the test the original problem was c^2=8c
test the c=0............0^2=8(0) 0=0 Good answer
test the c=8 8^2=8(8)...........64=64 Good answer

Answer 21

If it doesn't makes sense then as Luis Rivera says review and understand the principles of algebra.

Answer 22

k thanks for ur help

Answer 23

No problem, did you see how they check out?