Question

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Answer 1

the equivalent resistance isn't 65 ohm's?

Answer 2

R2 and R5 are in series. R1 and R4 are in series.

Let's combine these right away into an equivalent resistor R'. Note that R2 and R5 have the same equivalence as R1 and R4.
\(R' = 30 \Omega\)

Note that now we have an R' and an R' in parallel. Combining these into R''
\[R'' = \frac{R'^2}{2R'}\]

Note that R'' is in series with R3. Therefore,
\[R_{eq} = 5 \Omega + R'' = 20 \Omega\]

Answer 3

I worked this problem out. Let me take pictures and I'll upload them.

Answer 4

Let me know if you have any questions regarding my methodology.