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The region bounded by the curve y=x^2+1 and the line y=-x+3 is revolved around the line y=5 to generate a solid. Find the volume of that solid
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|dw:1331965647936:dw| Find volume using disc or washer method each cross-section is a ring with inner area and outer area the inner radius is 5-f(x) or 5-(-x+3) = x+2 outer radius is 5-g(x) or 5-(x^2 +1) = 4-x^2 \[V = \pi \int\limits_{-2}^{1}(4-x^{2})^{2} - (x+2)^{2} dx\]
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