Question

20g of a radiioactive substance reduces to 2.5g in 2079 day. What is the half life nd decay constant of the substance?

Answer 1

srinidhi

Answer 2

srinidhi plz explain.

Answer 3

srinidhi i have done.....

Answer 4

ok wt

Answer 5

T*k=2.303logA/A-XFROM THIS EQUATION U GET K AFTER THAT U HAVE TO FIND THE HALF LIFE JUST FETCH THE VALUE OF K IN THE EQUATION OF HALF LIFT K=0.693/TIME 4 HALF LIFE

Answer 6

time= half life x {log(intial amt/final amount) / log 2}

Answer 7

SRINDHI TUMKO SMJ ME AA GYA

Answer 8

Half life= 2079 / {(log20/2.5)/log2)}

=2079/(log8/log2)

Answer 9

ya

Answer 10

kya main galat hun kya...agar haan to tell

Answer 11

kaha

Answer 12

phele apko K ki value nikalni hogi .......k stands 4 rate contant ok.........after that usi k se tum half life nikal skte ho .......agr nhi smj me aaya to fir puch lena ok......me tumhe equation b bta skta hu

Answer 13

srinidhi r u there?

Answer 14

yes, i ws posting another question