Evaluate the integral 5/(x-1)sqrtx^2-2x-24dx. I ended up with (x-1)sqrt (x-1)^2-25. I got a=5 u=x-1 and du=1dx, but is it right for a=5? when you can't take the sqrt of a -25?

Question

turingtest · Answer

$$\int{5\over(x-1)\sqrt{x^2-2x-24}}dx$$is the problem?

anonymous · Answer

yeah

turingtest · Answer

and you cannot use trigonometric substitutions?

anonymous · Answer

i used 1/a arcsec absolute value u absolute value /a +c

turingtest · Answer

what is a?
what is u?
why absolute value?
 I'm just asking if you know how to use trig substitutions yet
do you know what I'm talking about?

anonymous · Answer

I ended up with the answer arcsec ( absolute value of (x-1)) /5 +c would that be right?

turingtest · Answer

not quite sorry, I have to go; here is the answer from wolfram http://www.wolframalpha.com/input/?i=+integral+5%2F%28%28x-1%29*sqrt%28x%5E2-2x-24%29%29dx ttl, good luck

anonymous · Answer

okay, thanks!