A 16μ F capacitor is joined in series with a 34μ F capacitor and a 12 Volts battery.
What is the potential difference across the first capacitor?What is the charge on the first capacitor?How much energy is stored by the first capacitor?

Question

A 16μ F capacitor is joined in series with a 34μ F capacitor and a 12 Volts battery.
 What is the potential difference across the first capacitor?What is the charge on the first capacitor?How much energy is stored by the first capacitor?

anonymous · Answer

Find equivalence capacitance of the circuit,
 Ceq=(16*34)/(16+34)=10.88

anonymous · Answer

Ceq=(16*34)/(16+34)=10.88 micro faraday.
 Hence the Net charge flows in the circuit=Ceq*V=130.56 micro coulomb
 hence the charge on first capacitor=130.56 micro coulomb
and potential difference across it=130.56/16=8.16Volt