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Determine the period, to the nearest tenth of radian, for the following function: y = 4 cos(4x + 6) - 1
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\[y=4\cos (4x+6)-1=4\cos 4(x+\frac{3}{2})-1\]
If you want to find the period, you should use this equation: \[coefficient of x = \frac{2\pi}{period}\] \[4=\frac{2\pi}{p}\]
\[4p=2\pi\] \[p=\frac{\pi}{2}\]
ok can u help me with this too If the maximum value of y = a cos x + 2.4 is 12.6, then the value of a, to the nearest tenth, is
Typically a cosine graph would go up to 1 and down to -1. Since this one is raised 2.4, it's centerline is y = 2.4 instead of y=0. It goes up to 12.6 which is 10.2 units above its centerline so its amplitude must be 10.2
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