How do I find the maximum volume of a funnel?
defferientiate the formula for the volume of a funnel
set it to zero
solve for the unknown is the last step ;)
wait no it's not.. then test to see which is max and which is min
a funnel is just a cone and tube...if you have to include that bottom part otherwise it is just a cone...cone formula - (1/3)pi(r)(h) tube formula: pi r^2 h
for a cone shaped funnel the volume is \[V=\frac{1}{3}\pi r^2 h\]
aaak dropped my r^2 on the cone...
I'm confused...In the problem, there's a wall around the funnel.. I don't know if that really changes the volume..
i don't think she knows calculus, so we're probably confusing her.
Nope, I don't.
but if all you want is the maximum...just plug in the height and radius...I don't think we are getting the whole problem...walls don't effect funnels
That's what I figured...
the wall around the funnel will set the values of the radius and height of the funnel so you need to take that into account
then use the volume formula to get the max volume, using the max values of radius and height, given the wall
that would be a heck of a problem for the wall to effect the funnel your funnel would need to be stretchy...aaak
but also dont forget that we have to account for the velocity and which the wind is creating orhtogonal angles witht the wall
and the surface tension of the stuff in the funnel...
and the temperature lol
Last question on this subject....there's an apothem. Do I also need to take that into account?
yes...use the apothem to get the height of the cone (h in the volume formula) \[l^2=r^2+h^2\] where l is the apothem
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