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@myininaya Find P[k+1] for the given P[k]. P[k]=(k/2)(3k-1)
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What about substituting K+1 in place of K ?
Well see, in an example, it shows otherwise.
It's only showing to input (k+1) for one of the k's, and not any of the other ones?
wow, nevermind, this makes me feel retarded.
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DONT EVEN ANSWER I FEEL SO STUPID NOW :'(
I am not sure what you are trying to say, but that is exactly the same thing I told you. :)
Oh well, don't worry about it :)
http://screensnapr.com/v/NwYLuS.png This example messed me up, thats why :P
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