Question

Stefan flips a coin four times. Which of the following shows the number of possible outcomes?
choices:

2

sixteen

sixty-four

8

Answer 1

The possible outcomes would be:
\[(H,H,H,H),(H,T,H,H) etc\]
Now, you've to find the number of four-lettered combinations you can make with H(Heads) and T(tails)
Take four blank spaces, to be filled by either H or T.
_ _ _ _
In how many ways can these spaces be filled?

Answer 2

@Luis Rivera how did you get that?
I suppose you used the m*n rule
For each flip you have two possibles
And we have 4 flips so that
means we have 2*2*2*2

Answer 3

4 ways?

Answer 4

That product does not =4

Answer 5

i was replying to mani jha sorry

Answer 6

Think again. Each space can be filled by either Heads or Tails. That means each space can be filled in 2 ways. So, the four spaces can be filled in 2*2*2*2 ways.
Get it?

Answer 7

I thnk i understand now

Answer 8

So what if we had 3 flippings?

Answer 9

2*2*2=8 ways.

Answer 10

And 6 flippings? lol

Answer 11

It will just be 2^x, if x is the no. of flippings..:p I think so

Answer 12

yes that right

Answer 13

2^x where x is the number of flippings

Answer 14

So what if we had that we were flipping a coin and tossing a die. What is the possible amount of outcomes?

Answer 15

plz have mercy

Answer 16

no more

Answer 17

lol jackjones you can do it

Answer 18

2 ways to choose the coin right?
6 ways to choose the die right?
the product of 6 and 2 will give you the number of possible outcomes

Answer 19

lol, She's making us do classwork! :P
right

Answer 20

ok jack i will stop

Answer 21

that pant pant wheeze

Answer 22

was to much

Answer 23

but i'll live... thank u for your help

Answer 24

I was just in a teaching mood lol

Answer 25

This is quite easy @Jackjones, if you flip x coins and roll y dice, then total number of possible outcomes:
\[2^{x}\times6^{y}\]
Now let me give you some homework(lol) - prove that the above is true.
Refer to the explanations of myininaya and mine, and think upon this.
If you can't, we are always here.