Two narrow slits are 0.4mm apart. The dark fringe of order 3 is 0.5 degrees from the central bright fringe. What is the wavelength of the light?
let use this as a guide
alright let me take a look.
ok so for sure d=0.4mm lol we got something :P
\[m* \lambda= d sin(\theta)\] let's plug in what we know m=3 d=.4mm theta=.5 degree \[3 \lambda=.4/1000 sin(.5)\] find \[\lambda\]
thats what i did!
but small question, why is it divided by 1000?
it is in millimeter, we want it in standard unit, meter
is it always in m? because the question wants it in nm so its after that we convert?
yes, all formulas tend to use standard units
damn, i thought you could use nm cuz for another i used that. ok that was stupid of me. let me submit my answer and we'll c if it is right. i really owe u tho man. thx :) what was ur answer?
let see if it is correct
0.015279m? = 15 279 068.26nm?
its wrong, but i i realised out error, its 3.5 not 3 because its a dark slit whioch is a minimum! :D THANKS A LOT MAN 4 attempts isnt pretty but at least we got the job done :D
np
wanna do another 1 :P?
sure, but I am not really good in optics
http://openstudy.com/study#/updates/4f6541fae4b079c5c6329551 heres the question, sry im having major lag it is not posting my responses lol
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