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Mathematics 9 Online
OpenStudy (anonymous):

Two narrow slits are 0.4mm apart. The dark fringe of order 3 is 0.5 degrees from the central bright fringe. What is the wavelength of the light?

OpenStudy (anonymous):

let use this as a guide

OpenStudy (anonymous):

alright let me take a look.

OpenStudy (anonymous):

ok so for sure d=0.4mm lol we got something :P

OpenStudy (anonymous):

\[m* \lambda= d sin(\theta)\] let's plug in what we know m=3 d=.4mm theta=.5 degree \[3 \lambda=.4/1000 sin(.5)\] find \[\lambda\]

OpenStudy (anonymous):

thats what i did!

OpenStudy (anonymous):

but small question, why is it divided by 1000?

OpenStudy (anonymous):

it is in millimeter, we want it in standard unit, meter

OpenStudy (anonymous):

is it always in m? because the question wants it in nm so its after that we convert?

OpenStudy (anonymous):

yes, all formulas tend to use standard units

OpenStudy (anonymous):

damn, i thought you could use nm cuz for another i used that. ok that was stupid of me. let me submit my answer and we'll c if it is right. i really owe u tho man. thx :) what was ur answer?

OpenStudy (anonymous):

let see if it is correct

OpenStudy (anonymous):

0.015279m? = 15 279 068.26nm?

OpenStudy (anonymous):

its wrong, but i i realised out error, its 3.5 not 3 because its a dark slit whioch is a minimum! :D THANKS A LOT MAN 4 attempts isnt pretty but at least we got the job done :D

OpenStudy (anonymous):

np

OpenStudy (anonymous):

wanna do another 1 :P?

OpenStudy (anonymous):

sure, but I am not really good in optics

OpenStudy (anonymous):

http://openstudy.com/study#/updates/4f6541fae4b079c5c6329551 heres the question, sry im having major lag it is not posting my responses lol

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