Question

is f(x) = x^2 - 16/x-4 continuous at x = 4? Give reason for the answer.

Answer 1

can you plug 4 in there and get a real number?

Answer 2

^ ill plug a 4 into you....

Answer 3

oh you know how much i love them 4s

Answer 4

:)

Answer 5

\[(x ^{2} - 16)/(x-4) = [(x-4)(x+4)]/(x-4) = x+4\]
So yes it is contiueous at x = 4
F(4) = 8

Answer 6

First try plugging in 4 before you do any factorization.
The function will be undefined ( i.e. division by zero)
Next try to factorize (rearrange)the function. In this case (x^2 -16) = (x+4)(x-4)
divide through by (x-4) and you are left with (x+4)
The function is now defined at x =4.
Now plug in 4 and it should be fine.

lol

Answer 7

Thank you very much

Answer 8

vw