Question

Determine the slope of the secant line for the curve defined by the equation:
f(x) = 3 x^2 + ( -5 )
for the points determined by x_0 = -6 and x_1 = -3.
The slope of the secant line is m = .

Answer 1

replace x by -6 and find
\[f(-6)\] e
then find
\[f(-3)\] so you will then have two points
\[(-6,f(-6))\] and
\[(-3,f(-3))\]
the slope will be
\[\frac{f(-3)-f(-6)}{-3-(-6)}\] or
\[\frac{f(-3)-f(-6)}{3}\]

Answer 2

f(-6) = 103
f(-3) = 22

points on the secant are (-6, 103) and (-3, 22)

m = (103 -22)/(-6 --3)

the gradient is m = -27

Answer 3

thanks