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Calc II - A thermometer is taken from a room where the temperature is 24 C to the outdoors, where the temperature is 9 C. After one minute the thermometer reads 11 C. Use Newton's Law of Cooling to answer the following question. When will the thermometer read 10 C?
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work with the difference in the temperatures
the initial difference is 24 - 9= 15 and after one minute the difference is 11-9=2 so it is cooling pretty damned fast
formula would be \[15\times (\frac{2}{15})^t\] and you want to set this equal to 1 (because 11 - 10 = 1) and solve for t
\[1=15\times (\frac{2}{15})^t\] \[\frac{1}{15}=(\frac{2}{15})^t\] \[t=\frac{\ln(\frac{1}{15})}{\ln(\frac{2}{15})}\]
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i get about 1.33 rounded so maybe 1.3 is your pick
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