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Let f(x) be the function \frac{1}{x+8}. Then the quotient \frac{f(5+h)-f(5)}{h} can be simplified to \frac{-1}{ah+b} for: a= and b=
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\[\frac{1}{x+8}\]
\[\frac{f(5+h)-f(5)}{h} =\frac{-1}{ah+b}\]
you should get \[\frac{-1}{(5+8)(5+h+8)}\]
\[\frac{-1}{13(13+h)}\] \[\frac{-1}{169+13h}\] i think
thats correct
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thanks
yw
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