lim t- squareroot of 3t +4 all over t->4 4 - t
have you tried multiplying the denominator and numberiation by the conjugate
Yes @lagrangeSon678 is right! multiply top and bottom by \[t+\sqrt{3t+4}\]
then what?
Then see if the top factors
and then see if something cancels on top and bottom
ontech you got it?
im still @ it.. trying.. not giving up
Let me know if you want me to show you the first step By the way don't multiply out the bottom
I'm glad you are trying to do it and learn it. That is really cool by the way. You get a medal! :)
ok.. will do.
got -4 for the answer.. not too sure if its correct
Let me check and show One sec...
\[\lim_{t \rightarrow 4}\frac{t-\sqrt{3t+4}}{4-t} \cdot \frac{t+\sqrt{3t+4}}{t+\sqrt{3t+4}}\] \[\lim_{t \rightarrow 4}\frac{t^2-(3t+4)}{(4-t)(t+\sqrt{3t+4})}\] \[\lim_{t \rightarrow 4}\frac{t^2-3t-4}{(4-t)(t+\sqrt{3t+4})}\] Did you get this far?
\[\lim_{t \rightarrow 4}\frac{(t-4)(t+1)}{-(t-4)(t+\sqrt{3t+4})}\]
Does anything cancel?
yes
the (t-4) will cancel right?
yep
So we have \[-\lim_{t \rightarrow 4}\frac{t+1}{t+\sqrt{3t+4}}\]
Now you just plug in 4 for t
\[-\frac{4+1}{4+\sqrt{3(4)+4}}\]
ok
do you got it? any questions with anything I did?
i completely understand what u did.. Thanks so very much. When doing it on my own, I just dont know when to do what.
Practice practice makes perfect!
Well no one is perfect lol
:)
i have two more with graphs.. do u think u could assist?
Go ahead.
it says sketch graph that illustrates the following : lim f(x) = infinity x->0+
and lim f(x) = -infinity x->0-
We get to make up the graph?
|dw:1332044779234:dw|
so It say we have as x approaches 0 from the right the curve is getting closer to infinity
|dw:1332044824258:dw|
Now it says as we get close to from the left we have that the curve is getting closer to -infinity you can use by graph by clicking that pencil to draw this part
so for the second one.. would it look something like this?|dw:1332045180741:dw|
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