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Mathematics 21 Online
OpenStudy (anonymous):

lim t- squareroot of 3t +4 all over t->4 4 - t

OpenStudy (anonymous):

have you tried multiplying the denominator and numberiation by the conjugate

myininaya (myininaya):

Yes @lagrangeSon678 is right! multiply top and bottom by \[t+\sqrt{3t+4}\]

OpenStudy (anonymous):

then what?

myininaya (myininaya):

Then see if the top factors

myininaya (myininaya):

and then see if something cancels on top and bottom

myininaya (myininaya):

ontech you got it?

OpenStudy (anonymous):

im still @ it.. trying.. not giving up

myininaya (myininaya):

Let me know if you want me to show you the first step By the way don't multiply out the bottom

myininaya (myininaya):

I'm glad you are trying to do it and learn it. That is really cool by the way. You get a medal! :)

OpenStudy (anonymous):

ok.. will do.

OpenStudy (anonymous):

got -4 for the answer.. not too sure if its correct

myininaya (myininaya):

Let me check and show One sec...

myininaya (myininaya):

\[\lim_{t \rightarrow 4}\frac{t-\sqrt{3t+4}}{4-t} \cdot \frac{t+\sqrt{3t+4}}{t+\sqrt{3t+4}}\] \[\lim_{t \rightarrow 4}\frac{t^2-(3t+4)}{(4-t)(t+\sqrt{3t+4})}\] \[\lim_{t \rightarrow 4}\frac{t^2-3t-4}{(4-t)(t+\sqrt{3t+4})}\] Did you get this far?

myininaya (myininaya):

\[\lim_{t \rightarrow 4}\frac{(t-4)(t+1)}{-(t-4)(t+\sqrt{3t+4})}\]

myininaya (myininaya):

Does anything cancel?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

the (t-4) will cancel right?

myininaya (myininaya):

yep

myininaya (myininaya):

So we have \[-\lim_{t \rightarrow 4}\frac{t+1}{t+\sqrt{3t+4}}\]

myininaya (myininaya):

Now you just plug in 4 for t

myininaya (myininaya):

\[-\frac{4+1}{4+\sqrt{3(4)+4}}\]

OpenStudy (anonymous):

ok

myininaya (myininaya):

do you got it? any questions with anything I did?

OpenStudy (anonymous):

i completely understand what u did.. Thanks so very much. When doing it on my own, I just dont know when to do what.

myininaya (myininaya):

Practice practice makes perfect!

myininaya (myininaya):

Well no one is perfect lol

OpenStudy (anonymous):

:)

OpenStudy (anonymous):

i have two more with graphs.. do u think u could assist?

myininaya (myininaya):

Go ahead.

OpenStudy (anonymous):

it says sketch graph that illustrates the following : lim f(x) = infinity x->0+

OpenStudy (anonymous):

and lim f(x) = -infinity x->0-

myininaya (myininaya):

We get to make up the graph?

myininaya (myininaya):

|dw:1332044779234:dw|

myininaya (myininaya):

so It say we have as x approaches 0 from the right the curve is getting closer to infinity

myininaya (myininaya):

|dw:1332044824258:dw|

myininaya (myininaya):

Now it says as we get close to from the left we have that the curve is getting closer to -infinity you can use by graph by clicking that pencil to draw this part

OpenStudy (anonymous):

so for the second one.. would it look something like this?|dw:1332045180741:dw|

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