Question

Find all the real zeros of the polynomial. Use the quadratic formula if necessary. P(x) = 2x^3 − 14x^2 + 8x + 48

Answer 1

First set it equal to 0 and divide out the common factor 2.

Answer 2

Then use synthetic division to find a rational zero.

Answer 3

i found all the possible zeros and found out that 3 is equal to 0 so i did the synthetic division and got 2x^2-8x-16 and from that point im not sure...

Answer 4

That is equal to 2(x^2-4x-8)

Answer 5

and do you use quad formula? a-1 b-4 and c-8? and 2 will just throw out?

Answer 6

It will not factor so plug it into the quadratic formula.

Answer 7

i did and got 4 +- square root -16 over 2

Answer 8

Let me check it out.

Answer 9

2 +-2sqrt3

Answer 10

how did you get that?

Answer 11

\[2(x^2-4x-8)=0\]

Answer 12

a=1, b=-4, c=-8

Answer 13

\[x=\frac{4\pm \sqrt{16-4(1)(-8)}}{2}=\frac{4\pm \sqrt{48}}{2}=\frac{4\pm4\sqrt{3}}{2}=2\pm2\sqrt{3}\]

Answer 14

oh i made a mistake on multiplication. thank you.