Devin wants to have equal amounts of room on all four sides of his ping pong table. A 5ft by 9ft table is placed in the center of a rectangular room that has an area of 221 square feet. What is the width of the clear space Devin will have on all sides of his table? How do I solve this?
find the area of the table (45) subtract from full area = 221 221-45 = 176 to determine the width only ....
176/4 = 44 ft
I need to use the completing the square method or something; I already tried to logic my way out of it like that. My teacher wouldn't accept that answer.
If by "room" we mean distance, and assume the room has the same proportions as the table, we end up with something like\[(5+2x)(9+2x)=221\rightarrow 4x^2+28x+45=221\rightarrow 4x^2+28x-176=0\]
I'm not sure this question is very well posed.
Your answer is good, i think, AnimalAin. I think that's how I'm supposed to solve it. My teacher didn't givem e a whole lot of practice on these types of problems -- I haven't run into them more than once or twice before.
Continuing....\[4(x^2+7x-44)=0\rightarrow (x+11)(x-4)=0\rightarrow x=4\]
Check step: dimension of the room would be 17 by 13, with area 221
...and he needs to tear out an end wall to extend the room at least another ten feet to be able to play table tennis.....
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