Question

use implicit differentiation to find dy/dx tan(xy)=x+y

Answer 1

( 1 + x^2 ).Dx [ tan ( x - y ) ] + tan ( x - y ). Dx ( 1 + x^2 ) = Dx ( y )

( 1 + x^2 ). sec^2 ( x - y ). Dx ( x - y ) + tan ( x - y ). ( 2x ) = dy/dx

( 1 + x^2 ). sec^2 ( x- y ). ( 1 - dy/dx ) + 2x. tan ( x - y ) = dy/dx

( 1 + x^2 ). sec^2 ( x - y ) + 2x. tan ( x - y ) = [ 1 + ( 1 + x^2).sec^2 (x-y) ].dy/dx

Answer 2

thatll show em :)

Answer 3

it'd help to stay on the question that is being answred instead of reposting it