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Mathematics 7 Online
OpenStudy (anonymous):

Simplify:

OpenStudy (anonymous):

OpenStudy (anonymous):

Can you type it lol

OpenStudy (anonymous):

125a^5/49B^5

OpenStudy (kinggeorge):

\[\Large{{10a^2 \over 7b^2} \over {25a^3 \over 14b^2}} = {10a^2 \over 7b^2}\cdot {14b^3 \over 25a^3} \]If you cancel terms, you get\[\large {4b \over 5a}\]

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