Question

Find the component form and magnitude of the indicated vector: Given that P=(-10,15) and Q=(-8,8), find the component form and magnitude of the vector sqrt5 QP

Answer 1

i assume QP means from Q to P therefore the vector is end - start; P-Q

Answer 2

sqrt(5) means we scale that result by a factor of sqrt(5) ; then take the length of it

Answer 3

What?

Answer 4

given that these are all terms of vector mathing, I have to wonder just what you means by "what?"

Answer 5

yep, thats the condition that I have presented

Answer 6

so what exactly do i do with it?

Answer 7

... subtract Q from P. what do we get?

P-Q = ?

Answer 8

<2,-7>

Answer 9

good, this is our vector from Q to P

scale that by sqrt(5) by multiplying the components by sqrt(5)

Answer 10

15-8 = 7 tho; so drop the negative there :)

Answer 11

isnt it q -p though?

Answer 12

-10--8 = -2
15-8 = 7 ; so the direction is imperitive.

<-2,7>

Answer 13

end - start = direction

Answer 14

we end in P and start at Q

Answer 15

\[2\sqrt{5} , 7\sqrt{5}\] ?

Answer 16

getting better, lets clean it up and make sure we know how we got there :)

<-2sqrt(5) , 7sqrt(5)>

Answer 17

P(-10,15)
-Q( -8, 8)
-----------
< -2, 7> *sqrt(5)

Answer 18

then the magnitude is to square the parts, add them together, and sqrt it

Answer 19

sqrt(4*5 + 49*5)

Answer 20

That's what I had gotten the first time and my teacher marked it off on my test...guess I'll go ask her if she got something wrong. Thanks so much!

Answer 21

your welcome; make sure youve simplified the sqrt(..) as far as possible

Answer 22

not that 5 and 53 have any perfect squares to pull out

Answer 23

Thank you so much!

Answer 24

youre welcome.