Question

A funnel with a height of 3.67 inches is shown below.
The funnel has a diameter of 1.87 inches that includes a wall that is 0.125 inches thick. What is the maximum volume of the funnel rounded to the nearest hundredth?
Answer 7.57 in3
3.36 in3
2.52 in3
2.22 in3

Answer 1

b

Answer 2

are you serious? or are you guessing?

Answer 3

i neve rguess

Answer 4

Hello? castillo you still there?

Answer 5

yes... just fed up with the calculation :( gimme some time

Answer 6

sprry! just making sure

Answer 7

i dunno .. my answer isn't even in one of these options :(

Answer 8

so the formula is V=(1/3)π(r^2)h ?

Answer 9

Yes. I am having trouble as well. Im thinking I need to find the volume of both and add them together. the inner and outer

Answer 10

nah... that's not possible..

Answer 11

the vol. of cone without the wall
= (1/3)π(r^2)h
= (1/3)π[(1.87-0.125x2)/2]^2 (3.67)
= (1/3)π (0.81)^2 (3.67)
= 2.52

Answer 12

MEDALS?

Answer 13

I thought it was bs also

Answer 14

sorry "b"

Answer 15

For futur ref please put the options synchronized properly.

Answer 7.57 in3
3.36 in3
2.52 in3
2.22 in3

to:

Answer
7.57 in3
3.36 in3
2.52 in3
2.22 in3

Answer 16

but the question says the wall is included in the diameter

Answer 17

Ohh ok sory haha! thats how it comes out sometimes

Answer 18

Duh Duh, I am sorry, Castillo is right.

Answer 19

\[\frac 13 \times \frac {(1.87-2 \times 0.125)}{2}^2 \times \pi \times 3.67 = 2.52153 \]

Answer 20

i got ya fool foolformath

Answer 21

you gys are smart in here. you must have like A's all throughout geometry and chemistry

Answer 22

poor me.. no one understand what i wrote :(

Answer 23

no I do.what is the volume of a semicircle