What is the equation in standard form of the line which passes through (–2, –3) and has a slope of
of ...
so standard form is y= mx +b
m will be your slope.. if we have a slope and two points we can use them to find b
1/2
okay so now we have y=(1/2)x +b
whats is one of your y's equal to?
and what about one of your x's?
I thought standard form is a(x)+b(x)=c
ahh yes you are right
yeah I don't know how to do this at all
okay we can still use what we have done
so y=(1/2)x +b and since we know that at one point y=-3 and x=-2 we can plug those in to find b
-3= (1/2)(-2) +b -3=-1 +b -2 = b
thats our b for all points
y=(1/2)x -2
that's what I ended up with but what would it be in standard form?
now just move the x term over
y - (1/2) x =-2
here's the answers I was given.. 2x + y = 4 2x – y = 4 x + 2y = 4 x – 2y = 4
we can simplfy our answer to look like theres if you would like, just multiply every term by -2
damn really..I didn't even think of that thank you so much!
yes i guess they are a little picky with that x term being positive... so you should always do that at the end
no problem... math is easy once ya get it!
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