Question

What is the period and frequency of a 10-pound weight oscillating (as a pendulum) on a 5-meter-long rope?

Answer 1

frequency=2pi/omega=2pi/sqrt(g/l)=2pi/sqrt(10/5)=2pi/sqrt(2) Hz

Answer 2

For a pendulum:
T(period)=\[2\pi \sqrt{l/g}\]
where l is the length of the rope and g is gravity.

f(frequency)=\[1/T\]
Therefore assuming that this is on earth the period is 4.487989505 and the frequency is 0.228169203.