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I need help A simple harmonic oscillator has spring constant k= 4.2 N/m , amplitude A= 13 cm , and maximum speed 4.2 m/s. What's the oscillator's speed when it's at x= 5.2cm?
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with v you can do many things since you have k you can use the formula v=omega/k to find omega
are you looking for an equation like this: x=Asin(omegat+phase constant) ?
umm i think its this equation....\[v= \sqrt{\left(\begin{matrix}k \\ m\end{matrix}\right)} (A^2-x^2)\]
but when i pull everything together the answer is not correct
ive never seen taht before tbh LOL
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oh sorry its max speed and not wave speed
ok, so v=Aomega you can get an omega
btw speed is -
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