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Physics 18 Online
OpenStudy (anonymous):

I need help A simple harmonic oscillator has spring constant k= 4.2 N/m , amplitude A= 13 cm , and maximum speed 4.2 m/s. What's the oscillator's speed when it's at x= 5.2cm?

OpenStudy (anonymous):

with v you can do many things since you have k you can use the formula v=omega/k to find omega

OpenStudy (anonymous):

are you looking for an equation like this: x=Asin(omegat+phase constant) ?

OpenStudy (anonymous):

umm i think its this equation....\[v= \sqrt{\left(\begin{matrix}k \\ m\end{matrix}\right)} (A^2-x^2)\]

OpenStudy (anonymous):

but when i pull everything together the answer is not correct

OpenStudy (anonymous):

ive never seen taht before tbh LOL

OpenStudy (anonymous):

oh sorry its max speed and not wave speed

OpenStudy (anonymous):

ok, so v=Aomega you can get an omega

OpenStudy (anonymous):

btw speed is -

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