Question

find the smallest value of A such that the function is increasing for all t in the interval (A,0)

f(t)=t^4 - 18t^2 +81

Answer 1

so i get 4t^3-36

Answer 2

when the derivative is taken

Answer 3

then?

Answer 4

(-3, 0)

Answer 5

the answer isnt a point

Answer 6

it should look like -3.456789

Answer 7

that's the interval from negative three to zero. when the function is graphed it is increasing on this interval, in addition to (3, infinity), (-3, 0) is the interval where the function is increasing with the lowest value of A.

Answer 8

what is the value?

Answer 9

thats what i need along with the work shown.

Answer 10

an interval is from a certain x, to a greater point of x and the region of the graph selected. when you look at the graph of the t function (original) it is obvious that the function is increasing from x=3 to x=0 where A is the smallest on an increasing interval

Answer 11

can you please just work it out?

Answer 12

i was helped with a similar problem earlier
http://openstudy.com/study#/updates/4f68a852e4b0f81dfbb584fe