m is the midpoint of AB . find the coordinates of the third point when A(2,7) AND M(1,6) whats b?
i know the answer is (0,5) but how do i do the work?
Mid point of two pts A(x1,y1) and B(x2,y2)=(x1+x2)/2and (y1+y2)/2
huh confuzed...
the coordinates of the mid point is the average of the coordinates of the points
\[\frac{x _{1}+x _{2}}{2}=1\] \[\frac{2+x _{2}}{2}=1\] \[2+x _{2}=2\] \[x _{2}=0\]
Repeat the process for the y coordinate of the midpoint.
sorry, got ahead of myself. A(2,7) and M(1,6) 2-1 = 1, so that means it is one unit over. A is at 2, M is at 1, so B is at 0 7-6=1, so this one is also one unit over, A is at 7, M is at 6, B is at 5. B(0,5)
\[\frac{y _{1}+y _{2}}{2}=6\] \[\frac{7+y _{2}}{2}=6\] \[7+y _{2}=12\] \[y _{2}=5\]
Mertsj's method is more proper. Especially for a more difficult problem when the answer is not given.
Mertsj's method is recommended for exams and HW.
thanks alott
yw
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