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OpenStudy (anonymous):
find the area of a triangle with sides of length 7 and 9 and included angle 72 degree.
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OpenStudy (amistre64):
the height if going to have something to do with the sin of 72
OpenStudy (amistre64):
side1*side2*sin 72 / 2
OpenStudy (anonymous):
|dw:1332298374511:dw|
OpenStudy (amistre64):
is that really an included angle?
OpenStudy (anonymous):
the right angle no
just the 72
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OpenStudy (anonymous):
so 38.52
OpenStudy (amistre64):
an "included angle" is one the is nestled inbwteen the side lengths mentions
OpenStudy (amistre64):
|dw:1332298527074:dw|
this is what you gave us in your information
OpenStudy (anonymous):
yea ... i drew it wrong i thought it was a triangle since it said find the area of a triangle
OpenStudy (amistre64):
:) then "height" can be regarded as 7sin(72) ; a base as 9
area tri = hb/2 = 9*7sin(72)/2
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OpenStudy (anonymous):
so height 6.66
OpenStudy (anonymous):
wait know i am confused
OpenStudy (anonymous):
now*
OpenStudy (anonymous):
\[1/2 \times7\times9\times \sin 72 = 29.95828026 \approx 30\]
OpenStudy (anonymous):
so that is how you do it?
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OpenStudy (anonymous):
yes .. half x 1st side x 2nd side x sine the angle included between them :)
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