Question

simple harmonic motion , d=8cos((3pi)/(4)t) answer the following questions:
Maximum: 8
Frequency: ????

Answer 1

Let's recall. \[x(t) = A \sin(\omega t)\]where \(\omega\) is the angular velocity.

Frequency can be expressed in terms of \(\omega\) as such\[f = {\omega \over 2 \pi}\]

Answer 2

4/2pi (Is that correct?)

Answer 3

I would imagine that \(\omega = 3 \pi /4\)

Answer 4

Ok I got it, I was looking at the wrong thing THANK YOU :)

Answer 5

What about this question:
0=8cos(3pi/4)(t)
So far I got: 0=8(-√2/2)(t)

Answer 6

What are you solving for with this equation?

Answer 7

It says: Determine the least positive value of t which d=0

Answer 8

You can just solve\[\cos({3 \pi \over 4} t ) = 0\]

Answer 9

We know that \(\cos(\pi/2) = 0\)

Therefore, \[{\pi \over 2} = {3 \pi \over 4} t\]