simple harmonic motion , d=8cos((3pi)/(4)t) answer the following questions:
Maximum: 8
Frequency: ????

Question

simple harmonic motion , d=8cos((3pi)/(4)t) answer the following questions:
Maximum: 8 
Frequency: ????

anonymous · Answer

Let's recall. $$x(t) = A \sin(\omega t)$$where $\omega$ is the angular velocity. 

Frequency can be expressed in terms of $\omega$ as such$$f = {\omega \over 2 \pi}$$

anonymous · Answer

4/2pi (Is that correct?)

anonymous · Answer

I would imagine that $\omega = 3 \pi /4$

anonymous · Answer

Ok I got it, I was looking at the wrong thing THANK YOU :)

anonymous · Answer

What about this question:
0=8cos(3pi/4)(t)
So far I got: 0=8(-√2/2)(t)

anonymous · Answer

What are you solving for with this equation?

anonymous · Answer

It says: Determine the least positive value of t which d=0

anonymous · Answer

You can just solve$$\cos({3 \pi \over 4} t ) = 0$$

anonymous · Answer

We know that $\cos(\pi/2) = 0$

Therefore, $${\pi \over 2} = {3 \pi \over 4} t$$