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Mathematics 13 Online
OpenStudy (anonymous):

{2/n^2} from n=5 to inf how do we know that this sequence is bounded below by zero?

OpenStudy (anonymous):

because 0 cannot be in the denominator

OpenStudy (anonymous):

then {(-1)^n+1} from n=1 to inf how do we know that it's bounded below by -1

OpenStudy (anonymous):

I don't understand the definitions of both bounded below and above, what exactly it means?

OpenStudy (anonymous):

"If there exists a number m such that for every n we say the sequence is bounded below. The number m is sometimes called a lower bound for the sequence." "If there exists a number M such that for every n we say the sequence is bounded above. The number M is sometimes called an upper bound for the sequence." from Paul's online Notes. here is the link if u r intersted: http://tutorial.math.lamar.edu/Classes/CalcII/MoreSequences.aspx

OpenStudy (anonymous):

that's what I am reading at the moment :)

OpenStudy (anonymous):

thanks anyway

OpenStudy (anonymous):

also in simple terms, when they say m is the lower bound, it means no value in the sequence/series can go below the value of m :)

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