Question

The first term in an arithmetic series is 2, while the sum of the first 8 terms of the series is 1472. What is the 8th term in the series? somebody help me

Answer 1

you got the value of a=2
use the formula
S=n/2 [2a+(n-1)d] then calculate d from here..
put it in t=a+(n-1)d

Answer 2

i dnt kno which number is n d or a

Answer 3

a = 2 , S8 = 1472

find the d first ,
8/2 ( 2(2) + 7d ) =1472
4 ( 4 + 7d ) = 1472
16 + 28d = 1472
d = 52

S8 - S7 = (2 (2) + 7(52) ) - (2 (2) + 6 (52 )
= solve it yourself.. you'll get the answer ;)

Answer 4

1st term known as 'a' . common difference known as ' d ' :)
'Sn' is sum of terms :)

Answer 5

*T8 = S8-S7
= (2 (2) + 7(52) ) - (2 (2) + 6 (52 )
= solve it yourself.. you'll get the answer ;)

Answer 6

im confused on how to solve it

Answer 7

1st term known as 'a' . common difference known as ' d ' :)
'Sn' is sum of terms :)

so , a = 2 , S8 = 1472

find the d first ,
8/2 ( 2(2) + 7d ) =1472
4 ( 4 + 7d ) = 1472
16 + 28d = 1472
d = 52

T8 = S8-S7
= ( 2(2) + 7(52) ) - ( 2(2) + 6(52 ) )
= 368 - 316
= 52*

8terms is 52 :)

Answer 8

*T8 is 8terms :)

Answer 9

is that help ??

Answer 10

n=total no. of terms in the sequence,here 8 terms , n=8
a=2...(a is the first term in the sequence)
d=?...(which is the common diff.)
S=sum of the 8 terms


s=n/2 [2a+(n-1)d]
1472=8/2 [2*2 + (8-1)*d]
364=7d
d=52
now we know that general term of a sequence is given by
T=a+(n-1)d (symbols have same meaning)
T=2+(8-1)*52
T=366

Answer 11

@qiqyn how can the 8th term be 52 if first term is 2 and the common difference is 52?????