Question

Find the real solutions of the equation:
6+√(2x-9)=x

Plzz!!! I really need to understand this, THX!!!

Answer 1

your equation is can be written as:
sqrt(2x-9) = x-6

squaring both sides you get:
2x-9 = (x-6)^2
2x-9 = x^2 -12x + 36 FOIL out the right side
0 = x^2 + 14x + 45 set 1 side to zero

this is not factorable (easy way) so use the quadratic formula.

Answer 2

Yup!

Answer 3

quadratic formula: \[x = \frac {-b \pm \sqrt{b^2-4ac}}{2a}\]
where a, b, c are the coefficients of ax^2 + bx + c = 0

Answer 4

a = 1, b = 14, c = 45. Don't forget to CHECK your answer because you wanted real solutions.

Answer 5

ok, what will be the solution set, then??
:))

Answer 6

9 will be the solution??