Find the real solutions of the equation:
6+√(2x-9)=x

Plzz!!! I really need to understand this, THX!!!

Question

Find the real solutions of the equation:
6+√(2x-9)=x

Plzz!!! I really need to understand this, THX!!!

anonymous · Answer

your equation is can be written as:
sqrt(2x-9) = x-6

squaring both sides you get:
2x-9 = (x-6)^2
2x-9 = x^2 -12x + 36    FOIL out the right side
0 = x^2 + 14x + 45        set 1 side to zero

this is not factorable (easy way) so use the quadratic formula.

anonymous · Answer

Yup!

anonymous · Answer

quadratic formula: $$x = \frac {-b \pm \sqrt{b^2-4ac}}{2a}$$
where a, b, c are the coefficients of ax^2 + bx + c = 0

anonymous · Answer

a = 1, b = 14, c = 45.  Don't forget to CHECK your answer because you wanted real solutions.

anonymous · Answer

ok, what will be the solution set, then??
:))

anonymous · Answer

9 will be the solution??