Question

(x^2-2x-15)/(x+3)
Isnt it has a vertical asymptote at x=1?
but how come if i graph it, it only shows a straight line but not approching to x=1
http://www.wolframalpha.com/input/?i=%28x%5E2-2x-15%29%2F%28x%2B3%29

Answer 1

vertical asymptote at x=-3. i know i graphed it too on th enet, but it seems we have misunderstood the command to the application. we need to redefine it.

Answer 2

srry i actually mean horizontal asymptote

Answer 3

actaully its best to factor the numerator first, and see what divided out. In this case the x+3 in the denminator will be gone

Answer 4

even from the graph you see that this will be a line

Answer 5

so there will be no horizontal asymptote in this case?
I dont know when the H.A is 0 and when is none..

Answer 6

correct there is no horizaontal asymptote.
There wil be no horixaontal asympotote when the degree of the numerator is higer than the denomonator

Answer 7

so if it is 5/x , there is still a H.A of 0?

Answer 8

yes and a veritcal asymptote at x=0

Answer 9

oh ok thank so much!! its clear now :)