Consider the combustion reaction of propane: C3H8(g) + 5 O2(g) ® 3 CO2(g) + 4 H2O(g), where DH = – 531 kcal/mol. If 6.70 ´ 104
kcal of energy is released in the reaction, how many grams of oxygen were consumed?

Question

Consider the combustion reaction of propane: C3H8(g) + 5 O2(g) ® 3 CO2(g) + 4 H2O(g), where DH = – 531 kcal/mol.  If 6.70 ´ 104
kcal of energy is released in the reaction, how many grams of oxygen were consumed?

anonymous · Answer

Blanking on how to set this up....

istim · Answer

I can't help much, but maybe I can help guide. Is this stoichiometry?

anonymous · Answer

basically, its a unit in my book on energy
i know this is very simple and i should be able to do this but i just dont want to get it wrong

istim · Answer

Also, what's DH??

anonymous · Answer

delta H

anonymous · Answer

enthalpy or heat of reaction which is the energy needed to break a covalent bond

istim · Answer

Oh man. This university stuff? Also, to rperesent exponents use ^

anonymous · Answer

U of Illinois

istim · Answer

Aww. Bugger. Do you know about stoichiometry? I think you could apply that knowledge here.

anonymous · Answer

yeah, i do. i just dont know what to do with the unit of kcal they give me. there are no moles of propane to use so i'm stumped

anonymous · Answer

well 1 mole...

istim · Answer

I'm stumped too. Sorry about that.