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Find unit tangent and unit normal of: r(t)=<2sin(t), 5t, 2cos(t)>
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seems like an eerily familiar problem
We should probably, begin by finding the the velocity function since it is tangent to the position function
after differentiating we obtain: v(t)=<2cost,5,-2sint> Now we have to find the magnitude of V. Sqrt(4cos^2t+25+4sin^2t> Which simplifies to : sqrt(4+25)-->sqrt(29)
So, the unit tangent is give by v/lvl, thus we have: |dw:1332423189026:dw|
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