What volume of nitrous oxide can be produced from the decomposition of 0.55 moles of ammonium nitrate using the equation NH4NO3

Question

anonymous · Answer

At what pressure and temperature does the decomposition occur at?

anonymous · Answer

Use dimensional analysis 35g N2O x 1 mol N2O / (44g N2O) x 80g NH4NO3 /(1 mole NH4NO3) = 63.6g NH4NO3

anonymous · Answer

they havent specifies the temp so i assume w take it is standard conditions of temp and pressure
first u got to write the equation for clear understanding
|dw:1332696177777:dw|
1 mole of nh4no3 gives me 1 mole of nitrous oxide so how many moles for 0.55 moles nh4no3?
0.55 moles so what volume it occupies
22.4 l is occupied by 1 mole under STP conditions so for 0.55 moles?
find out