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OpenStudy (anonymous):
11^x=12 In terms of logarithms
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OpenStudy (anonymous):
\[b^x=y\iff x=\log_b(y)\]
OpenStudy (anonymous):
you should be able to switch back and forth quickly
OpenStudy (anonymous):
by "should" i mean it would help you immensely in your math class if you can go back and forth without agony
OpenStudy (anonymous):
yeah still work in progress haha just started learning them
OpenStudy (anonymous):
i keep getting the incorrect answer I am unsure of how to enter it into the calculator. DO i have to type 11 before the log(12)?
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OpenStudy (anonymous):
it is not a calculator exercise unless you are solving for x
OpenStudy (anonymous):
Iforgot to mention that I am solving for x, sorry.
OpenStudy (anonymous):
oh i misread. you are solving for x right?
OpenStudy (anonymous):
ok then
\[b^x=y=\iff x=\frac{\ln(y)}{\ln(b)}\]
OpenStudy (anonymous):
change 'o base formula
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OpenStudy (anonymous):
\[x=\frac{\ln(12)}{\ln(11)}\]
OpenStudy (anonymous):
ohhhhh i see! how did you know to change it to natural log/natural log?
OpenStudy (anonymous):
You could have used \[\log_{10} \]You get the same answer.
\[x=\log_{10}12/\log_{10}11 \]
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