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solve.... i'll draw the equation
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\[(3\sqrt{2} (\cos 45 + i \sin 45 )^{3}\]
keep in a+bi form
\[(\frac{\sqrt{3}}{2}(\cos(45)+i \cdot \sin(45))^3\] \[r e^{i \cdot \theta}= r (\cos(\theta)+i \cdot \sin(\theta) )\] \[(r e^ {i \theta})^3=(r \cos(\theta) + i \sin(\theta) )^3\] \[(\frac{\sqrt{3}}{2} e ^{i \frac{\sqrt{2}}{2}})^3= ( \frac{\sqrt{3}}{2} \cos(\frac{\sqrt{2}}{2})+i \cdot \sin(\frac{\sqrt{2}}{2}))^2\] So what do you get when you in the following form: \[r' e^{ i \theta'}\] \[(\frac{\sqrt{3}}{2} e^{i \cdot \frac{\sqrt{2}}{2}})^3\] \[\text{What is } r' \text{ and what is } \theta' ? \]
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