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MIT 8.01 Physics I Classical Mechanics, Fall 1999 19 Online
OpenStudy (anonymous):

Relative acceleration: Need help with this problem. Please see the attached JPG

OpenStudy (anonymous):

OpenStudy (radar):

It would appear since the acceleration is upward and the collar can only move at a path which is 45 degrees from the vertical, the acceleration force in that direction would be .707(4 meter/sec^2) Just a swag lol.

OpenStudy (anonymous):

Thanks for replying but book answer says that a=7.49 m/s^2 at an angle of 22.8 degrees measured from neg-x axis counterclockwise.

OpenStudy (radar):

It was just a guess (with some wrong thinkin)

OpenStudy (mani_jha):

|dw:1332554742554:dw| The collar C would have two accelerations - one in the upper direction, and one along the shaft AB. Can you find the resultant of these two vectors? \[a=\sqrt{a 1^{2}+a2^{2}+2a1a2\cos 45}\] a1=4 a2=4cos45

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