Use the quadratic formula to solve the equation. x^2-x=-2 Please help, I dont' know why this one is so confusing to me, but I can't get it.
x^2-x=-2 x^2-x+2 =0 ax^2 +bx +c =0 \[x=(-b \pm \sqrt{b^2-4ac)}/(2a)\]
put the corresponding value to the formula
x^2-x+2=0 Use quadratic formula: ax^2-bx+2=0 a=1, b=-1, c=2
so the x's are equal to 1 right?
since Δ<0, you will not get real solutions..
i is the imaginary number\[i=\sqrt{-1}\]
so was my answer close? I thought I was completely wrong and deleted it.
Hmm.. close but not correct... don't be afraid to make mistakes!
Sorry this is really confusing to me.
So, can you try again to get the answer?
I can try, but I don't understand still how it works. With no real numbers, it totally confuses me.
show you steps please~
trying to go over every thing you have said so far to see if I can comprehend it.
i deleted my answer.. i hope you can try...perhaps you can start with substituting the numbers into the formula and ask whatever you don't understand so we can help
I don't understand the imaginary number. Where does that come in?
what is the formula I need to use? Is it the ax^2+bx+2?
ax^2 +bx +c =0 is the general form of a quadratic equation. Before you apply the quadratic formula, you have to make the equation into general form first
then use the quadratic formula \[x=(-b \pm \sqrt{b^2-4ac)}/(2a)\]
Ok now my nerves are gone. I have gone beyond confusion now. LOL
that means you understand it now?
so when you say to put it into general form...you mean its not already in general form the way that it is?
No that means that confusion is an understatement. Now I am just plain lost!
x^2-x=-2 it is not in a general form
but when you add 2 on both sides, it is in the general form
ok
so you 'll get x^2 -x +2 =0
right ok I got that.
match the coefficient with a, b,c in the general form
a=1, b=-1, c=2
Then put these value into the quadratic formula, and you'll get x
*values
so do I really put in the numbers 1 when putting the values into the formula?
put a=1, b=-1, c=2 into the formula
ok got that...here is what it looks like; |dw:1332557688893:dw|
Join our real-time social learning platform and learn together with your friends!