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Mathematics 8 Online
OpenStudy (anonymous):

(Please help!) One way to describe the concentration of an acid is as a percent by volume. For example, in 40 mL of a 30% acid solution, the volume of pure acid is 40 x 30/100 or 12 mL, and the volume of water is 40-12 or 28 mL. If 5 mL of pure acid is mixed with 20 mL of water to give 25 mL of acid solution, the concentration of the solution is given by 5/25 x 100% = 20 %. If water is mixed with 50 mL of 40% acid solution, write an equation that describe the acid concentration, C(x), as a function of the volume of water added, x.

OpenStudy (anonymous):

Function is: C(x) = 20/(50 + x)*100% And so, what is the acid concentration after 10 mL of water have been added?

OpenStudy (mertsj):

Just replace x with 10.

OpenStudy (anonymous):

that's it?

OpenStudy (anonymous):

is 33 1/3% the same as 33.333% ?

OpenStudy (mertsj):

\[c(10)=\frac{20}{60}=.333(100)=33.3 percent\]

OpenStudy (mertsj):

yes

OpenStudy (anonymous):

ohh, okay thank you!

OpenStudy (mertsj):

yw

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