Question

A 0.1647g of hydrocarbon sample is going through combustion process. It produces 0.5694g of CO2 and 0.0845g of H2O. Determine the percentage of these elements in this hydrocarbon.

Answer 1

i got the answr

Answer 2

Can u please explain me? I don't know these concepts but excited to learn.

Answer 3

aadarsh it is just maths that is there above determining percentage
1 mole of Co2 has how much grams in it and how much grams of carbon?

Answer 4

1 mol of CO2 = 16 grams
12 grams of carbon, rite?

Answer 5

CxHy + 3/2 O2------> xCO2 + Y/2H20 take out mole of CO2 as u are provided mass and molecularweight

Answer 6

mass of co2 in 1 mole? yes 12 g of carbon is there in how many grams of co2?
oxygen ATOM has mass no 16 use that

Answer 7

Sorry, mass of 1 mol CO2 = 12 + 16*2 = 44

Answer 8

yes ! tahts it u got the answer almost...........so now how much carbon is there in above apecified mass of co2?

Answer 9

that is in 0.5694 grams? how much carbon?

Answer 10

12/44 * 0.5694?

Answer 11

yeah same way find out the mass of oxygen in co2 then mass of hydrogen in h2o
then wat u learnt in math
to find the percent of an element in a given substance wat do u do?

Answer 12

Yeah!!!!!!!! Got it!!!!!!!!!

Answer 13

first wat i learnt was that never to avoid doing something because u think u cant do it..u may never know that u actually know it well....in other words dont underestimate urself (or over estimate)
this was a lesson i learnt and wanted to share with u!

Answer 14

Yeah that's true. But sometimes fear overcomes me. Still learning to cope up wiht that.

Answer 15

:)

Answer 16

CxHy + 3/2 O2------> xCO2 + Y/2H20
x=0.5694/44 x=0.01(almost)
y=0.0845/18
y=0.04
so simplest ratio is CH4
and percentage comp is 12/16 x 100 = 75 for Carbon
and 4/16 x 100= 25 for H