Question

Cl2 + 2 KOH = KCl + KClO + H2O
3 KClO = 2KCl + KClO3
4 KClO3 = 3KClO4 + KCl
How much Cl2 is needed to prepare 400g of KClO4???
in grams
Ive got 38.056 gm

Answer 1

my answeris 38.056 g please verify the answer

Answer 2

I did not get that answer.
400 grams of KClO4 is equal to 2.89 mols.
3 KClO makes 1 KCLO3 and 4 KClO3 makes 3 KClO4.
This means you have a ratio of 4:3 for KClO3 to KClO4. Simplifying that ratio gives you 4/3:1 ratio. Now multiply 4/3 by 2.89 and that gives you the amount of KClO3 you need (in mols).

Now looking at the second equation, 3 KClO gives you only one mol of KClO3 so that means you have to multiply the amount of KClO3 you got previously by 3 to figure out how much KClO you need (once again in mols). Now Cl2 and KClO are in a 1:1 ratio so just multiply the number of mols of KClO by the molecular weight of Cl2 to get the answer.

Answer 3

just tell me Im right r wrong

Answer 4

ok