Question

Prove this identity sin^2 Θcsc^2 Θ = sin^2 Θ = cos^2 Θ

Answer 1

Think you have too many equality symbols

Answer 2

That is what the question I got for homework is asking. I don't understand it.

Answer 3

You copied it wrong. It should be:
\[\sin ^2x \csc ^2x-\sin^2x=\cos^2x\]

Answer 4

\[\sin^2(\theta)+\cos^2(\theta)=1\]
\[1+\cot^2(\theta)=\csc^2(x) => \csc^2(x)-1=\cot^2(x)\]
So maybe it is suppose to say
\[\sin^2(\theta) \csc^2(\theta)-\sin^2(\theta)=\cos^2(\theta)\]
\[\sin^2(\theta)(\csc^2(\theta)-1)=\sin^2(\theta) \cdot \cot^2(x)=\sin^2(\theta) \cdot \frac{\cos^2(\theta)}{\sin^2(\theta)}\]

Answer 5

No this is the problem:
sin^2 Θcsc^2 Θ = sin^2 Θ = cos^2
Oh well, I am going to ask my teacher if she wrote the equation wrong

Answer 6

\[\sin ^2\theta \times\frac{1}{\sin ^2\theta}- \sin ^2\theta=\cos ^2\theta\]

Answer 7

She did.

Answer 8

she totally wrote it wrong
so i totally agree with mr. mert here
she meant to write the way we said
just change it
you might be only one who does the problem (And might get bonus :))

Answer 9

Okay I will do that Thank You:)