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Chemistry 14 Online
OpenStudy (anonymous):

What is the electron configuration of Br, Z=35?

OpenStudy (rogue):

The expanded out form would be...\[Br: 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^5\]The condensed form would be\[Br: [Ar] 4s^2 3d^{10} 4p^5\]

OpenStudy (anonymous):

yea what Rogue said..just full the orbitals then write the electronic configuration closest to that of a noble gas

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