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Mathematics 12 Online
OpenStudy (anonymous):

Simplify 1/2x^−3y^−4z^7 .

OpenStudy (anonymous):

2x

OpenStudy (anonymous):

6x

OpenStudy (anonymous):

it's 2x

OpenStudy (anonymous):

64x9x4

OpenStudy (anonymous):

Its 6x

OpenStudy (anonymous):

type the question again

OpenStudy (anonymous):

ITS 6X

OpenStudy (anonymous):

is it like everything in the denominator?

OpenStudy (anonymous):

Simplify 1/2x^−3y^−4z^7 .

OpenStudy (anonymous):

2x

OpenStudy (anonymous):

yess

OpenStudy (anonymous):

whats the power of x in 2x?

OpenStudy (anonymous):

and y? in 3y

OpenStudy (anonymous):

-3

OpenStudy (anonymous):

-4

OpenStudy (anonymous):

Simplify 1/2x^−3 y^−4 z^7 .

OpenStudy (anonymous):

\[=1/(2x ^{-3})(y ^{-4})(z ^{7)}\]

OpenStudy (anonymous):

like this?

OpenStudy (anonymous):

yea

OpenStudy (anonymous):

it can be like \[2x ^{3}y ^{4}/z ^{7}\]

OpenStudy (anonymous):

you can take the negative x value to the numerator

OpenStudy (anonymous):

actualy the 2 stays the denominator

OpenStudy (anonymous):

\[x ^{3}y ^{4}/2z ^{7}\]

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

\[=x ^{3}y ^{4}/2z ^{7}\]

OpenStudy (anonymous):

yea this is the correct one..

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