Ask your own question, for FREE!
Mathematics 15 Online
OpenStudy (anonymous):

does anyone one know how to do the Solve for x: x + 4 < 2 I need some help please

OpenStudy (anonymous):

x=-4

OpenStudy (anonymous):

5x – 2 > -12

OpenStudy (anonymous):

the thrid one is -4x + 3 < 15

OpenStudy (anonymous):

You would add -2 to both sides... 5x > -10 Then you would divide both sides by 5.... x > -2

OpenStudy (anonymous):

kell1170 how would i set that up ?

OpenStudy (anonymous):

can you help me with these last few please i only have this one -4x + 3 < 15 and two more please

OpenStudy (anonymous):

Whoops didn't show my work. Sorry. Okay you have 5x - 2 > -12. So you take and add 2 both sides +2 +2 Then you just have 5x > -10 so you divide both sides by 5 to get x by itself. x > -2

OpenStudy (anonymous):

Your next one is -4x+3>15 You subtract 3 from each side -3 -3 Then you have -4x > 12. Now divide by -4 each side x> -3

OpenStudy (anonymous):

the next two are 7(x – 1) > -14 and the last one is -4(x – 2) < 2 ( x + 1)

OpenStudy (anonymous):

7(x-1) > -14. First, you multiply everything in the parenthesis by 7. You now have 7x-7 > -14. Then, add 7 to both sides. +7 +7 Now you have 7x > -7. Now divide both sides by 7 to get x by itself. x> -1

OpenStudy (anonymous):

Your last one is -4(x-2) < 2(x+1). You distribute the numbers to everything in the parenthesis and you now have -4x+8 < 2x+2 (Remember two negatives=a positive always) +4x +4x Now, you can do this two different ways, but I'm gonna show you the way I would do it. I would add -4x to each side. You now have 8 < 6x+2 so you subtract 2 from each side -2 -2 and you have 6 < 6x so you divide each side by 6 to get X by itself and you end up with 1 < x :)

OpenStudy (anonymous):

I have a question did i do this one right ? x + 4 < 2 x>-4

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!