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Mathematics 19 Online
OpenStudy (anonymous):

The diagram shows a set of coordinate axes superimposed on the cross section of a sloping roof of height, h metres and width w metres. The equation of one half of the cross section is y= -0.7x+1.9.

OpenStudy (anonymous):

a) What is the equation of the other half of the cross section? b) What is the width of the roof, w, to the nearest tenth of a metre? c) State the domain and range of each function that states each half of the roof.

OpenStudy (anonymous):

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OpenStudy (anonymous):

Why is the answer for a) y = 0.7x + 1.9 and b) 5.4 m?

OpenStudy (asnaseer):

for (a), the line on the left has the same y-value as the line on the right if you replace x by its negative.

OpenStudy (asnaseer):

for (b), when the line crosses the x-axes, the value of y is zero. so we get: 0 = -0.7x + 1.9 if you solve this for x, you will get half the width.

OpenStudy (anonymous):

ohh, okay, so why shouldn't it not -0.7x + 1.9

OpenStudy (anonymous):

wait, what is the x- axis? like the horizontal axis? So I basically double it?

OpenStudy (asnaseer):

yes - the x-axis is the horizontal axis

OpenStudy (asnaseer):

and yes, you double the resulting value to get w

OpenStudy (anonymous):

ohh, okay. So when the line basically passes the horizontal axis then y-value becomes o ex. say (6,0)? Ohh..

OpenStudy (asnaseer):

for a) you are given: y = -0.7x + 1.9 so, to get the equation for the line on the left, you replace x with -x to get: y = -0.7(-x) + 1.9 = 0.7x + 1.9

OpenStudy (anonymous):

why do I replace x with -x? Oh because the x-values on the left-side are negative?

OpenStudy (asnaseer):

yes - I think you are beginning to understand these types of equations now :)

OpenStudy (anonymous):

ohh, thank you!

OpenStudy (asnaseer):

yw

OpenStudy (asnaseer):

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