Question

lim θ→0 sin(cos 8θ)/sec 5θ

Answer 1

lim θ→0 sin(cos 8θ)/cos8θ . cos 8θ/sec5θ then I get cos 8θ. cos 5θ

but i don't know how to continue it

Answer 2

\[\lim_{\theta \rightarrow 0}\frac{ \sin (\cos(8 \cdot \theta))}{\sec(5 \cdot \theta)}\]
Why don't you just use direct substitution :)

Answer 3

\[\sec( 5 \cdot 0)=\sec(0)=1\]

Answer 4

Bottom is not zero so we are good

Answer 5

cos 8θ=0 right? is sin 1 is 1?

Answer 6

i tried 1 for the answer but it is wrong

Answer 7

\[\sin( \cos(8 \cdot 0))=\sin(\cos(0))=\sin(1)\]
We have sin(1)/1=sin(1)
We are done
No sin(1) totally does not =1

Answer 8

thankkksss you are right, I gave you medal already

Answer 9

lol ok thanks for the medal
you are sweet