Question

What is the coefficient in fron of the"x"^2 when (2x+3)^4 is expanded?

Answer 1

How did you get this?

Answer 2

do you just leave the 3 out of it?

Answer 3

i used Pascal's triangle:
(a + b)^2 = 1 2 1
(a + b)^3 = 1 3 3 1
(a + b)^4 = 1 4 6 4 1

the right side of the equal signs are just the coefficients of the binomials expanded.

Answer 4

sorry, I misread your question. I thought your were looking for the coefficient of the leading term. you want the coefficient of the x^2 term right?

Answer 5

Yes, the coefficient if front of x^2.

Answer 6

ok, so...
you see the 6 in the (a + b)^4?

Answer 7

yes

Answer 8

that's the term 6a^2b^2. since your a=2x, b=3
6*(2x)^2*(3)^2 = 6*4x^2*9
= 6*4*9*x^2
= 216x^2

your coefficient for the x^2 term is 216

Answer 9

still faster than if you were to multiply the whole thing out...

Answer 10

SO is that the answer because it says the coeficcient in front of x^2

Answer 11

SO is that the answer because it says the coeficcient in front of x^2

Answer 12

yes... http://www.wolframalpha.com/input/?i=expand+%282*x%2B3%29%5E4

Answer 13

Okay thank you so much for your help!

Answer 14

np